Continuous
probability distributions
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1.
Data
are uniformly distributed between the values of 6 and 14.
Determine the value of f (x).
a=6 b=14
Tentukan nilai f
(x).
f (x) =
f (x) =1/14-6
f (x) =
f (x) = 0.125
What are the mean and standard deviation
of this distribution?
Apa deviasi mean dan standar distribusi
ini?
µ=
µ=
µ=
µ =
10
σ =
σ =
σ =
σ =
2.3094010768
What is the probability of randomly
selecting a value greater than 11?
Apa
probabilitas secara acak memilih nilai lebih besar dari 11?
P(x
> 11) =
P(x
> 11) =3/8
P(x
> 11) =0.375
What is the probability of randomly selecting
a value between 7 and 12?
Apa probabilitas secara acak memilih nilai
antara 7 dan 12?
P(7
<x< 12) =
P(7
<x< 12) = 5/8
P(7
<x< 12) =0.625
2. Assume a normal distribution and find
the following probabilities.
a. P(x < 20 ; m = 25 and s = 4)
z =
z =
z=
-5/4
z =
-1.25
Table
A.5 nilai untuk z = -1.25 adalah: 0.3944
P(x
< 20) = 0,5000-0.3944
P(x
< 20) =0.1056
b. P(x ≥ 77 ; m = 60 and
s = 9)
z =
z =
z=
17/9
z =
1.8889
Table
A.5 nilai untuk z = 1,889 adalah: 0.4699
P(x
≥
77 )= 0.5000- 0.4699
P(x ≥
77 )= 0.0301
c. P(x > 47 ; m = 50 and
s = 8)
z =
z =
Z =
-3/8
z = 0.375
Table A.5 nilai untuk z = 0.375 adalah:
0.1443
P(x > 47) = 0,5 + 0,1443
P(x > 47 = 0,6443
d. P(13
< x < 29 ; m = 20
and s = 5)
z =
z =
Z =
-7/5
z = -1.4
Table A.5 nilai untuk z = -1.4 adalah:
0.4192
z =
z =
Z =
9/5
z =
1,8
Table
A.5 nilai untuk z = 1,8 adalah: 0.4641
P(13 <
x < 29)=0.4641+ 0.4192
P(13 <
x < 29)=0.8833
e. P (x ≥ 100 ; m = 90 and s = 3)
z =
z =
Z =
10/3
z = 0.333
Table A.5 nilai untuk z = 0.333 adalah: 0.1293
P (x
≥ 100 ) = 0,5 - 0.1293
P (x
≥ 100) = 0.3707
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