Selasa, 08 Oktober 2019

contoh soal Continuous probability distributions


Continuous probability distributions



1.      Data are uniformly distributed between the values of 6 and 14.
Determine the value of f (x).
            a=6 b=14
            Tentukan nilai f (x).
              f (x) =
              f (x) =1/14-6
              f (x) =
              f (x) = 0.125

What are the mean and standard deviation of this distribution?
     Apa deviasi mean dan standar distribusi ini?
µ=  
µ=  
µ=
µ = 10

σ =  
σ = 
σ =
σ = 2.3094010768


What is the probability of randomly selecting a value greater than 11?
Apa probabilitas secara acak memilih nilai lebih besar dari 11?
P(x > 11) =
P(x > 11) =3/8
P(x > 11) =0.375

 What is the probability of randomly selecting a value between 7 and 12?
   Apa probabilitas secara acak memilih nilai antara 7 dan 12?
P(7 <x< 12) =
P(7 <x< 12) = 5/8
P(7 <x< 12) =0.625







2.   Assume a normal distribution and find the following probabilities.
a.   P(x <  20 ;  m  = 25  and  s  = 4)
z =  
z =  
z= -5/4
z = -1.25

Table A.5 nilai untuk z = -1.25  adalah: 0.3944
P(x <  20) = 0,5000-0.3944
P(x <  20) =0.1056

b.   P(x  ≥ 77 ;  m  = 60 and   s  = 9)

z =
z =  
z= 17/9
z = 1.8889

Table A.5 nilai untuk z = 1,889  adalah: 0.4699
P(x  ≥ 77 )= 0.5000- 0.4699
 P(x  ≥ 77 )= 0.0301

c.   P(x  > 47 ;  m  = 50 and   s  = 8)
 z =
z =
Z = -3/8
 z = 0.375

 Table A.5 nilai untuk z =  0.375 adalah:  0.1443
                P(x  > 47) =      0,5 +      0,1443
                P(x  > 47 = 0,6443

d.   P(13  < x < 29 ; m  = 20 and   s  = 5)
 z =
z =
Z = -7/5
 z = -1.4
   
 Table A.5 nilai untuk z =  -1.4 adalah:  0.4192
   z =
z =
Z = 9/5
z = 1,8

Table A.5 nilai untuk z =  1,8 adalah: 0.4641
  P(13  < x < 29)=0.4641+  0.4192
  P(13  < x < 29)=0.8833


e.   P (x ≥ 100 ;  m  = 90 and  s = 3)
z =
z =
Z = 10/3
 z = 0.333
     Table A.5 nilai untuk z =  0.333 adalah:   0.1293
                P (x ≥ 100 ) = 0,5 -  0.1293
                P (x ≥ 100)  = 0.3707

contoh soal Discrete probability


contoh soal Discrete probability


1.   Solve for the probabilities of the following binomial distribution problems by using the binomial formula.
a.   If n = 11 and   p = 0,23, what is the probability that x = 4? q = 0,77

0,148


b.   If n =   6 and   p = 0,50, what is the probability that x 1, q = 0,5

6 .
0,09374


c.   If n =   9 and   p = 0,85, what is the probability that x 7? q = 0,15


6 .
0,259667

d.   If n = 14 and  p = 0,70,what is the probability that x … 3?

P(X £ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)
P(X £ 3) = (1,59)     + (4,84)       + 6,77 + 0,000
P(X £ 3)= 13,2
2.   Use Table A.2, Appendix A, to find the values of the following binomial distribution problems.
      a.   P(x  = 12 ;  n  = 20   and   p = 0,60)
            tabel A ® prob.1,000
      b.   P(x  <  4  ;  n  = 10   and   p = 0,30)
            P(x  <  4  )® n  = 10   p = 0,30
            Tabel A
x
prob
3
0.6496
2
0.3828
1
0.1493
0
0.0282
jml
1.2099

      c.   P(x  ≥ 10 ;  n  = 12   and   p = 0,80)
P(x  ≥ 10) n  = 12      p = 0,80
Tabel A
x
prob
10
0.283468
11
0.206158
12
0.068719
jml
0.558345

      d.   P(x  > 15 ;  n  = 18   and   p = 0,40)
P(x  > 15) ® n  = 18    p = 0,40

            Tabel A
x
prob
16
2.37E-05
17
1.86E-06
18
6.87E-10
jml
2.5561E-05




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